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MEDAN MAGNET
,• induksi magnetik

kawat melingkar
α = 45°
i = 6 A
a = 3π×10⁻² m
B = __?

B = (α/360°) μ₀ i / (2π a)
B = ⅛ • 4π×10⁻⁷ • 6 / (2 • 3π×10⁻²)
B = ½ × 10⁻⁵ = 6×10⁻⁶ T ✓