saya mau tanya dong,kalo di soal logaritma ada seperti ini bagaimana caranya ? tolong dijawab ya disertakan cara nya juga terimakasih ^x+1 log(2x+5) = ²log²24 -

2log^2.24 - 2log^2.6 = (2log 24)^2 - (2log 6)^2
= (2log 24 + 2log 6) ( 2log 24 - 2log 6)
= 2log (24.6) (2log (24/6)
= 2log 144x 2log 4
= 2log (2^4.3^2) x 2log 2^2
= ( 4+ 2. 2log 3) x 2
= ( 8 + 4. 2log 3)
= 2log 2^8 + 2log 3^4
= 2log (256 x 81)
= 2log 20736
----------------
2log 144
= 144log 20736
= sudah, tapi ini mungkin bisa membantu.

²log².24 - ²log².6 = (²log 24)² - (²log 6)²
==============================
(²log 24)² - (²log 6)²
= (²log(8 . 3))² - (²log(2 .3))²
= (²log 8 + ²log 3)² - (²log 2 + ²log 3)²
Misalkan
a = ²log 3
maka
(²log 8 + ²log 3)² - (²log 2 + ²log 3)²
= (3 + a)² - (1 + a)²
= 9 + 6a + a² - (a² + 2a + 1)
= 8 + 4a
= 4(2 + a)
====================================
2 . ²log 12 
= 2 . (²log 4 + ²log 3)
= 2 . (2 + a)
====================================
(²log 24)² - (²log 6)² dibagi   2 . ²log 12 
= 4(2 + a) / 2(2+a)
= 2
======================================
sehingga pers. menjadi

(x+1) log(2x+5) = 2
⇔ 2x + 5 = (x+1)²
⇔ 2x + 5 = x² + 2x + 1
⇔ x² - 4 = 0
⇔ (x - 2) (x + 2) = 0
⇔ x = 2  atau  x = - 2
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HP : {-2 , 2}