1. (3 per 4 ) ^-² =.... 2. ( 3^6 : 3^3 ) : 3^2 =..... 3. ( 2^6 x 2^2 ) : 2^3 =..... Mohon dibantu Please penting Sekarang

Question

Matematika Diposting : 2017-10-13 Diupdate : 2017-10-26 koko141

Pertanyaan

1. (3 per 4 ) ^-² =....
2. ( 3^6 : 3^3 ) : 3^2 =.....
3. ( 2^6 x 2^2 ) : 2^3 =.....

Mohon dibantu Please
penting Sekarang

Answer 1

(3/4)²
=3²/4²
=9/16

(3^6 / 3^3) / 3²
=3^3 / 3²
=3

(2^6.2²) / 2^3
=2^8 / 2^3
=2^5
=32