smk analis kelas 10 4log√128-4log8=... tolang jawab ya pertanyanya

Kalo ada yg ga ngerti tanya lagi aja. Atau bisa liat sifat2 algoritma di mbah google

4logV128 - 4log8
= 4log(V128/8)
= 4log(128^(1/2)/8)
= 2^2log((2^7)^(1/2)/2^3)
= 2^2log(2^(7×1/2)/2^3)
= 2^2log(2^(7/2)/2^3)
= 2^2log 2^(7/2 -3)
= 2^2log 2^(7/2 - 6/2)
= 2^2log 2^(1/2)
= [log 2^(1/2)]/[log 2^2]
= [1/2 log 2]/[2 log 2]
= (1/2)/2
= 1/2 × 1/2
= 1/4