jika p=2 dan q=3, serta r=p2+2qp+q2 berapakah pqr?

P=2, q= 3
r= p²+2qp+q²
=2² +2(3×2) + 3² = 4 + 12 +9 = 25
Pqr = 2 × 3 × 25 = 150

p = 2
q = 3
r = p^2 + 2pq + q^2
r = 2^2 + 2(2)(3) + 3^2
r = 4 + 12 + 9
r = 25

pqr
= 2(3)(25)
= 150