tentukan turunan dari fungsi berikut : 1) y= 1 / (x^2 +1) 2)y=x^2 cos x 3) x-1 / x^3+2

jawab

y = 1/(x² +1)
y = (x² +1)⁻¹
y' = -1 (x² +1)⁻²
y' = -1/(x²+1)²

y = x² cos x
y = u v
y' = u' v + uv'
y' = (2x)(cos x) + (x²)(-sin x)
y' = 2x cos x - x² sin x

y = (x+1)/(x³+2)
y = u/v
y' = (u'v - uv')/v²
y' = {(1)(x³+2) - (x-1)(3x²)} / (x³+2)²
y' = (x³+2 - 3x³ + 3x²) / (x³+2)²
y' =  (-2x³ + 3x² + 2) / (x³+2)²