Matematika

Pertanyaan

3log12+3log9-3log4+3log3

2 Jawaban

  • ³㏒(12.9/4.3)=³㏒81=³㏒3⁴=4.³㏒3=4.1=4
  • = 3log12 + 3log9 - 3log4 + 3log3
    = 3log4×3 + 3log3^2 - 3log4 + 1 (aloga = 1)
    = 3log4+3log3 + 2 3log3 - 3log4 + 1 {(alogb+c = alogb + alogc) dan (aloga^n = n aloga)}
    = 3log4 + 1 + 2 × 1 - 3log4 + 1
    = 3log4 + 1 + 2 - 3log4 + 1
    = 3log4 - 3log4 + 4
    = 4

    maap kalau misalnya ada yang silap

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