Matematika

Pertanyaan

Ada yang bisa nomer 1,2&3 ? Tolong dong pake cara butuh banget
Ada yang bisa nomer 1,2&3 ? Tolong dong pake cara butuh banget

1 Jawaban

  • Nomor 1:
    [tex] \frac{PR}{RT} = \frac{PQ}{ST} [/tex]
    [tex] \frac{PR}{21} = \frac{7,5}{18} [/tex]
    PR = [tex] \frac{21 . 7,5}{18} [/tex]
    PR = 8,75 cm

    Nomor 2:
    [tex] \frac{CE}{CB} = \frac{DE}{AB} [/tex]
    [tex] \frac{CE}{CE + BE} = \frac{30}{36} [/tex]
    36 CE = 30 × (CE + 4)
    36 CE = 30 CE + 120
    36 CE - 30 CE = 120
    6 CE = 120
    CE = 20 cm

    Nomor 3:
    [tex] \frac{XY}{24} = \frac{WZ}{40} [/tex]
    [tex] \frac{XY}{24} = \frac{15}{40} [/tex]
    XY = [tex] \frac{24  .  15}{40} [/tex]
    XY = 9 cm

    [tex] \frac{WX}{32} = \frac{WZ}{40} [/tex]
    [tex] \frac{WX}{32} = \frac{15}{40} [/tex]
    WX = [tex] \frac{32  .  15}{40} [/tex]
    WX = 12 cm
    YZ = 12 cm

    Keliling = WX + XY + YZ + WZ
    Keliling = 12 + 9 + 12 + 15
    Keliling = 48 cm