JANGAN JAWAB ASAL ASALAN! Nilai x yang memenuhi pertidaksamaan : [tex] \sqrt{4x+3} ~\leq~ \sqrt{11-8x} ~-~ 1 [/tex] adalah ... A . 4 ≤ x ≤ 36 B . (37/36) ≤ x ≤

[tex]4x+3\geq 0\rightarrow x\geq -\frac{3}{4}\\11-8x\geq 0\rightarrow x\leq \frac{11}{8}\\\\\left(\sqrt{4x+3}+1\right)^2\leq\left(\sqrt{11-8x}\right)^2\\(4x+3)+1+2\sqrt{4x+3}\leq 11-8x\\\left(2\sqrt{4x+3}\right)^2\leq \left(7-12x\right)^2\\4(4x+3)\leq 49-168x+144x^2\\144x^2-184x+37\geq 0\\(4x-1)(36x-37)\geq 0\\x\leq\frac{1}{4}\vee x\geq\frac{37}{36}\\\\(x\geq -\frac{3}{4}\wedge x\leq\frac{11}{8}\wedge x\leq\frac{1}{4})\vee(x\geq -\frac{3}{4}\wedge x\leq\frac{11}{8}\wedge x\geq\frac{37}{36})\\-\frac{3}{4}\leq x\leq\frac{1}{4}\vee\frac{37}{36}\leq x\leq\frac{11}{8}[/tex]