Matematika

Pertanyaan

Matriks A= [ 0 -1 ] [3 4] B= [5 2 ] [x+1 x -1] jika det [AB] = -3 , nilai x=

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1 Jawaban

  • AB=[0 -1][3 4] x [5 2][x+1 x-1]
         =[0-x-1 0-x+1][15+4x+4 6+4x-4]
         =[-x-1 -x+1][4x+19 4x+2]

     det AB= (-x-1)(4x+2)-(4x+19)(-x+1)
            -3 = (-4x²-6x-2)-(-4x²-15x+19)
            -3 = 9x-21
             9x= 18
              x= 18/2
              x = 2

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