tolong djwb persamaan linear 3 variabel plis...

4x+y-2z=0...(1)
2x-3y+3z=9.....(2)
-6x-2y+2z=0...(3)
substitusi
4x+y-2z=0>>>>>>y=-4x+2z
substitusi ke pers 2
2x-3y+3z=0
2x-3(-4x+2z)+3z=0
2x+12x-6z+3z=0
14x-3z=0...(4)

substitusi kan kepers3
-6x-2y+2=0
-6x-2(-4x+2z)+2z=0
-6x+12x-4z+2z=0
6x-2z=0
-2z=-6x:0
z=0....(5)

subistusikan z kepers 4
14x-3z=0
14x-3(3x)=0
14x-9x=0
15x=0
x=0:15
x=0
substitusi kan keperawanan 1


4x+y-2z=0...(1)
4(0)+y-2(3x)=0
0+y-0=0
y=0:0
y=0

jadi nilainya
x=0
y=0
z=0