Jika x1 dan x2 memenuhi persamaan 1/2 log ( 2x^2 - 3) - 1/2 log (4x) = - 2 maka nilai x1 + x2 =

1/2log (2x^2 - 3)/4x = 1/2log (1/2)^-2
(2x^2 - 3) / 4x = 2^2
(2x^2 - 3) = 16x
2x^2 - 16x - 3 = 0
x1 + x2 = -b/a
= - -16/2.
= 16/2
= 8