tolong jawab kan sush ni pake cara please

a)
diket
m = [tex] \dfrac{3}{5} [/tex]

y = mx + c
*substitusi titik (5,9) dan m = [tex] \dfrac{3}{5} [/tex]*
9 = ([tex] \dfrac{3}{5} [/tex]).5 + c
9 = 3 + c
c = 6

Jadi, persamaanya y = [tex] \dfrac{3}{5} [/tex]x + 6

b)
m = -[tex] \dfrac{1}{2} [/tex]

y = mx + c
3 = (-[tex] \dfrac{1}{2} [/tex]).6 + c
3 = - 3 + c
c = 6

Persamaannya
y = -[tex] \dfrac{1}{2} [/tex]x + 6