Tolong di jawab sama caranya kalo bisa caranya di poto makasihh

y ² = 2 - x
x = 2 - y²
x² = (2 - y²)² = 4 - 2y² + y⁴
============================

∫ (x + x²) dy  {0....1}
= ∫ (2 - y² + 4 - 4y² + y⁴) dy  {0.....1}
= ∫ (6 - 5y² + y⁴) dy  {0.....1}
= 6y - 5y³/3 + y⁵/5  {1.....0}
= 6(1) - 5(1)³/3 + (1)⁵/5 - 0
= 6 - 5/3 + 1/5
= 6 - 25/15 + 3/15
= 6 - 22/15
= 90/15 - 22/15
= 68/15

∫ x dy  {-1....1}
= ∫ (2 - y²) dy {-1....1}
= 2y - y³/3 {1....-1}
= 2(1) - (1)³/3 - 2(-1) + (-1)³/3
= 2 - 1/3 + 2 - 1/3
= 4 - 2/3
= 12/3 - 2/3
= 10/3

jawab
y² = 2 - x
x = 2  - y²

a)
₋₁¹∫ x dy =  ₋₁¹ ∫(2 -y²) dy 
= [ 2x - 1/3 y³]¹₋₁
= 2(2) -1/3(2)
=  10/3

b)
₀¹∫ (x + x²) dy  = ₀¹∫ (2-y²) +(2-y²)² dy
= ₀¹∫ 2 -y² + 4 - 4y² +y⁴  dy
= ₀¹∫ y⁴  - 5y² +6  dy
= 1/5 y⁵  -5/3 y³ + 6 y]¹₀
= 1/5 (1) - 5/3(1) + 6(1)
= 68/15