tentukan himpunan : 1. ^6log6^x = 1+2x 2. ^2log(2^x-3) = 2 3. ^5x+7log64 = ^3log4

karena nomor 1 dan 2 gampang. jadi sya jawab yang no. 3 aja

^(5x+7) log 64 = ³log4
^(5x+7) log 4³ = ³log4
3 × ^(5x+7) log 4 = ³log4
^(5x+7) log 4 = ³log4 / 3
^(5x+7) log 4 = ³log4 / ³log3³
^(5x+7) log 4 = ^(3³) log 4
⇔ 5x+7 = 3³
⇔ 5x + 7 = 27
⇔ 5x = 20
⇔ x = 4

no. 2

²log(2ˣ - 3) = 2
²log(2ˣ - 3) = ²log4
⇔ 2ˣ - 3 = 4
⇔ 2ˣ = 7
⇔ x = ²log 7