Matematika

Pertanyaan

3x-y+z=10. 2x+3y-z=8. x+y-2z=-10 sistem peesamaan linear tiga variabel

2 Jawaban

  • 3x - y + z = 10
    2x + 3y - z = 8
    x + y - 2z = - 10

    x + y - 2z = - 10
    x = - 10 - y + 2z

    2x + 3y - z = 8
    2(- 10 - y + 2z) + 3y - z = 8
    - 20 - 2y + 4z + 3y - z = 8
    - 2y + 3y + 4z - z = 8 + 20
    y + 3z = 28

    3x - y + z = 10
    3(- 10 - y + 2z) - y + z = 10
    - 30 - 3y + 6z - y + z = 10
    - 3y - y + 6z + z = 10 + 30
    - 4y + 7z = 40

    y + 3z = 28|× 4
    - 4y + 7z = 40|× 1

    4y + 12z = 112
    - 4y + 7z = 40
    __________ +
    19z = 152
    z = 8

    y + 3z = 28
    y + 24 = 28
    y = 28 - 24
    y = 4

    x = - 10 - y + 2z
    x = - 10 - 4 + 16
    x = - 14 + 16
    x = 2

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