diketahui f(x) =ax+b jika f(-1) =2 dan f(2) =11 tentukan rumus fungsi f

◆ f(x) = ax + b
→ f(-1) = -1a + b = 2
→ f(2) = 2a + b = 11 (Eleminasi)

◆ Mencari a
→ -3a = -9
→ a = (-9) ÷ (-3)
→ a = 3

◆Mencari b
→ f(2) = 3 x 2 + b = 11
→ f(2) = 6 + b = 11
→ b = 11 - 6
→ b = 5

◆Rumus Fungsi f
→ f(x) = 3x + 5

F(-1)= -1a+b=2
F(2)=2a+b=11
jadi
F(-1)=-1.3+5=2
F(2)=2.3+5=11
jadi rumus nya
f(×)=3x+5