kak tolong bantu jawab beserta caranya

a)
x^2 + 4x + 4 = 0(x + 2)(x + 2) = 0

 x + 2 = 0x = -2

b)
2x^2 - x - 5 = 0
a = 2
b = -1
c = -5

[tex] x_{1,2} = \dfrac {-b +- √(b²-4ac)}{2a} [/tex]
[tex] x_{1,2} = \dfrac {1 +- √((-1)² - 4(2)(-5))}{4} [/tex]
[tex] x_{1,2} = \dfrac {1 +- √41}{4} [/tex]

c)
2x^2 + 4x - 6 = 0
x^2 + 2x - 3 = 0
(x + 3)(x - 1) = 0
x + 3 = 0
x = -3
atau
x - 1 = 0
x = 1

d)
x^2 - x + 1 = 0
a = 1
b = -1
c = 1
[tex] x_{1,2} = \dfrac {-b +- √(b²-4ac)}{2a} [/tex]
[tex] x_{1,2} = \dfrac {1 +- √((-1)² - 4(1)(1))}{2} [/tex]
[tex] x_{1,2} = \dfrac {1 +- √-3}{2} [/tex]
*tidak mungkin karna √-3 tidak real*

e)
x^2 + x - 30 = 0
(x + 6)(x - 5) = 0
x + 6 = 0
x = -6
atau
x - 5 = 0
x = 5