Bantu dong SOAL Matriks nomer 3 sama 6. MOHON BANTUANNYA

3a) |A| = (-5)1 - (p+4)(p-2)
0 = -5 - (p²+2p-8)
= -p²-2p+3
p²+2p-3 = 0
(p+3)(p-1)= 0
p = -3 dan p = 1

Hp (p = -3 atau p = 1)


b) |A| = {(p-2)p(p-3)+0+0} - {(4)(2)(p-3)+0+0}
0. = (p-2) p (p-3) - (8p-24)
= (p²-2p)(p-3) - (8p-24)
= p³-5p²+6p -8p +24
= p³-5p²-2p+24

1. -5. -2. 24
3. 3. -6. -24
_____________
1. -2. -8. 0
p²-2p - 8 = 0
(p-4) (p+2) = 0
p = 4 , p = -2

Hp { p= -2 atau p = 3 atau p = 4}