permisi kawannn....... minta tolong jawaban dan penjelasan nomor 15

jawab

AB = 2 BC → p  = 2l

panjang kawat =  32
2p + 2l + 2 diagonal = 32
2p+ 2l + 2 √(p²+l²) = 32
2(p+l+ √(p² +l²) = 32
p + l + √(p²+l²) = 16
2l + l + √((2l)² + l²) = 16
3l + √(5l²) = 16
3l + l √5 = 16
l(3 + √5)= 16
l = (16)/ (3 + √5)
l = (16)(3 -√5)/  (9-5)
l =16 (3-√5) / 4
l = 4 (3 - √5)
l = 12 - 4√5
AD = l = 12 - 4√5