Nomor 2 saja jangan semua

[tex]\left(f\circ g\right)(2)=f\left(g(2))=f\left(2^2+1\right)=f(5)=5-\frac{1}{5}=\frac{24}{5}[/tex]

[tex]\left(g\circ f\right)(2)=g\left(f(2))=g\left(2+\frac{1}{2}\right)=g\left(\frac{3}{2}\right)=\left(\frac{3}{2}\right)^2+1=\frac{9}{4}+1=\frac{13}{4}[/tex]