log log (x + 3) + log 2 = log log 16x. nilai x1.x2 =...

Log (log (x + 3)) + Log 2 = log log 16x
Log (2 . log (x + 3)) = log (log 16x)
2 . log(x+3) = log16x
log(x+3)² = log16x
(x+3)² = 16x
x² + 6x + 9 = 16x
x² - 10x + 9 = 0
(x - 9)(x - 1) = 0
x1 = 9
x2 = 1

jadi x1 . x2 = 9 . 1 = 9

jawab

log log(x+3) + log 2  = log log (16x)
log { 2 . log (x+3)} = log {log (16x)}
2 log (x+3) = log (16x)
(x+3)² = 16x
x² +6x + 9 = 16x
x² -10x + 9 = 0
x1.x2 = c/a  = 9/1 = 9