ayo bantuin. integral tentu . no.4

∫ (4x - 5) dx  {1....c}   = 6

= ∫ (4x - 5) dx {1....c}    =  6
= 4x²/2 - 5x {c ......1}    = 6
= 4(c)²/2 - 5c - 4(1)²/2 + 5(1)    = 6
= 2c² - 5c - 2 + 5     = 6
= 2c² - 5c + 3 = 6
= 2c² - 5c - 3 = 0
= (2c + 1)(c - 3) = 0
⇔ c = -1/2    atau  c = 3

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