Sistem persamaanx+y-z=24,2x-y+2z=4,x+2y-3z=36 nilai x, y, z?

x+y-z=24
2x-y+2z=4
x+2y-3z=36

Eliminasi dikurangi
x+2y-3z=36
x+y-z=24
=>  y-2z=12

eliminasi dikurangi
x+y-z=24 dikalikan 2 jadi
2x+2y-2z=48
2x-y+2z=4
=> 3y-4z = 44

Eliminasi dikurangi
y-2z=12 di kali 3
3y - 6z = 36
3y-4z = 44
=> -2z= -8      z=4

y-2z=12   => y-2(4)= 12   =>  y=20
x+y-z=24 =>  x + 20 - 4 = 24   =>  x=8

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