Himpunan penyelesaian dari2×^-2×-12=0

2x² - 2x - 12 = 0
2(x² - x - 6) = 0
(x² - x - 6) = 0
(x - 3)(x + 2) = 0
x = 3   atau   x = -2

jadi HP : {-2 , 3}

2x² - 2x - 12 = 0
(2x + 4) (x - 3) = 0
2x + 4 = 0
2x = -4
x = -2
atau
x - 3 = 0
x = 3

HP = {-2, 3}