Nilai dari ^3log18+^3log9-^3log2

LOGAritma

³log 18 + ³log 9 - ³log 2
= ³log (18 × 9/2)
= ³log 81
= ³log 3⁴
= 4 ✔

Mapel : Matematika

Jawaban:

[tex] ^3log18 + ^3log9 - ^3log2 \\ = ^3log(\dfrac{18\times 9}{2}) \\ = ^3log81 \\ = ^3log3^4 \\ = 4 \times ^3log3 \\ = 4[/tex]

Semoga membantu...