Matematika

Pertanyaan

cos 2 theta + sin^2 theta ÷ cos theta
cos 2 theta + sin^2 theta ÷ cos theta

2 Jawaban

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  • Trigonometri

    (cos 2θ + sin² θ) / cos θ

    cos 2θ
    = cos (θ + θ)
    = cos θ . cos θ - sin θ . sin θ
    = cos²θ - sin²θ

    -->
    ( cos²θ - sin²θ + sin²θ)/cosθ
    = (cos²θ) / cos θ
    = cos θ

    Opsi A