Matematika

Pertanyaan

2 sin ( 315derajat + x ). sin ( 45derajat + x ) = - cos 2x

1 Jawaban

  • 2.sin(315° + x).sin(45° + x) = -cos 2x
    2.sin(360°-(45°-x)).sin(90°-(45°-x)) = -cos 2x
    2.(-sin(45°-x)).cos(45°-x) = -cos 2x
    -(2.sin(45°-x). cos (45°-x)) = -cos 2x
    -sin(90-2x) = -cos 2x
    cos 2x = cos 2x
    *terbukti*

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