Tolong dikerjakan secepatnya ya....

(2x+3y)3=8x3+36x2y+54xy2+27y3

Using Binomial theorem expansion,

(x+y)3=x3+3x2y+3xy2+y3

Hence (2x+3y)3

= (2x)3+3(2x)2⋅3y+3(2x)(3y)2+(3y)3

= 8x3+3⋅4x2⋅3y+3⋅2x⋅9y2+27y3

= 8x3+36x2y+54xy2+27y